java – 无法在基本类型int上调用nextint()

码：

    Scanner yesNo = new Scanner(System.in);
    Scanner input = new Scanner(System.in);
    // 
    //answer auto set to no. goes to first if, then asks for confirmation,
    // then check answer again and go to if, else if or else. 
    //
    int answer = 0;
    while (answer != 1)
        if (answer == 0) {
            System.out.println("In how many seconds should we detonate?");
            int bomb = input.nextInt();
            //this number will be used later in else if (answer == 1)
            System.out.println("Is " + bomb + " seconds correct? 1 for yes, 0 for no");
            answer = answer.nextInt();
            //error above "Cannot invoke nextint() on the primitive type int"
            //Need this to grab a number from user to assign a new value to answer

做什么？谢谢.

可能你想做

answer = input.nextInt();